Frequency effect in a series RC: When the frequency of a sinusoidal source applied to a series RC circuit is decreased, what happens to the circuit's impedance magnitude?

Difficulty: Easy

Correct Answer: increases

Explanation:


Introduction / Context:
The impedance of a capacitor depends on frequency through Xc = 1/(2πfC). In a series RC, the overall impedance magnitude is |Z| = √(R^2 + Xc^2). Understanding how |Z| varies with frequency is key to filter behavior and signal attenuation.


Given Data / Assumptions:

  • Series RC network.
  • Source frequency f is decreased.
  • Component values fixed (R and C constant).


Concept / Approach:

As f decreases, Xc increases since Xc is inversely proportional to frequency. With a larger capacitive reactance vector, the magnitude of the vector sum with R increases or at least does not decrease if R stays fixed.


Step-by-Step Solution:

Xc = 1/(2πfC): decrease f ⇒ increase Xc.|Z| = √(R^2 + Xc^2): increasing Xc increases |Z|.Therefore, the impedance magnitude increases when frequency is reduced.


Verification / Alternative check:

Limiting cases: As f → 0, Xc → ∞, so |Z| → ∞ (open-circuit behavior). As f → ∞, Xc → 0, so |Z| → R (minimum).


Why Other Options Are Wrong:

'Decreases' contradicts Xc behavior. 'Remains the same' would require Xc constant. 'Doubles' is an arbitrary numeric claim without basis.


Common Pitfalls:

Mixing capacitor behavior with inductor behavior (which increases with frequency); forgetting the square-root relationship.


Final Answer:

increases

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