Kinematic vs dynamic viscosity equality: A liquid shows 1 cP (centipoise) equal to 1 cSt (centistoke) when its density equals 1 g/cm³. Which common liquid satisfies this approximately at room temperature?
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AWater
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BMercury
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CCarbon tetrachloride
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DNone of these
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EGlycerol
Answer
Correct Answer: Water
Explanation
Introduction / Context:Dynamic viscosity (μ) and kinematic viscosity (ν) are related by density: ν = μ / ρ. In cgs units, if μ is in cP and ρ in g/cm³, then ν is in cSt. Thus, when ρ ≈ 1 g/cm³, the numerical values of μ (cP) and ν (cSt) coincide, a handy check for common liquids near room temperature.
Given Data / Assumptions:
- Relation: ν (cSt) = μ (cP) / ρ (g/cm³).
- Looking for a liquid with ρ ≈ 1 g/cm³ at ambient conditions.
- Typical room temperature ≈ 20–25°C.
Concept / Approach:Pure water at ~20°C has density ~0.998 g/cm³ and dynamic viscosity ~1.0 cP, yielding kinematic viscosity ~1.0 cSt (more precisely ≈ 1.002 cSt). Therefore, water satisfies the condition closely, making “1 cP ≈ 1 cSt” a commonly used rule-of-thumb for water at ambient conditions.
Step-by-Step Solution:
Use ν = μ / ρ with μ ≈ 1 cP, ρ ≈ 1 g/cm³ for water.Compute: ν ≈ 1/1 = 1 cSt.Therefore, the liquid is water.Verification / Alternative check:Property tables list at 20°C: μ_water ≈ 1.002 cP, ρ_water ≈ 0.998 g/cm³ ⇒ ν ≈ 1.004 cSt, validating the approximation.
Why Other Options Are Wrong:
- Mercury: density ~13.6 g/cm³, so ν ≪ μ numerically.
- Carbon tetrachloride and glycerol have densities far from 1 g/cm³ and very different viscosities.
- “None of these” is incorrect because water satisfies the condition.
Common Pitfalls:Mixing SI and cgs units or forgetting that equality holds only when density ≈ 1 g/cm³.
Final Answer:Water.