What will be the output of the program? #include int main() { int i=4; switch(i) { default: printf("This is default "); case 1: printf("This is case 1 "); break; case 2: …

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What will be the output of the program? #include<stdio.h> int main() { int i=4; switch(i) { default: printf("This is default "); case 1: printf("This is case 1 "); break; case 2: printf("This is case 2 "); break; case 3: printf("This is case 3 "); } return 0; }

This is default This is case 1
This is case 3 This is default
This is case 1 This is case 3
This is default

Correct Answer: This is default This is case 1

Explanation:

In the very begining of switch-case statement default statement is encountered. So, it prints "This is default".

In default statement there is no break; statement is included. So it prints the case 1 statements. "This is case 1".

Then the break; statement is encountered. Hence the program exits from the switch-case block.

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