Method hiding with new: what is printed? namespace CuriousTabConsoleApplication { class Baseclass { public void fun() { Console.Write("Base class "); } } class Derived1 : Baseclass { new void fun() { Console.Write("Derived1 class "); } } class Derived2 : Derived1 { new void fun() { Console.Write("Derived2 class "); } } class Program { static void Main(string[] args) { Derived2 d = new Derived2(); d.fun(); } } }

Introduction / Context:
This problem illustrates method hiding using the new modifier in C#. Unlike virtual/override dispatch, new creates a new member that hides the inherited one when the compile-time type matches the derived class.

Given Data / Assumptions:

• Baseclass.fun, Derived1.fun, and Derived2.fun are all non-virtual and hidden with new.
• d is declared as Derived2 and instantiated as Derived2.

Concept / Approach:
For non-virtual methods, the invoked method is selected based on the compile-time type of the reference. Because d has compile-time type Derived2, calling d.fun() invokes Derived2.fun(), printing “Derived2 class”. No base methods are called.

Step-by-Step Solution:

Verification / Alternative check:
Cast the reference to base types to observe different outputs: ((Derived1)d).fun() prints “Derived1 class” and ((Baseclass)d).fun() prints “Base class”.

Why Other Options Are Wrong:
They assume virtual dispatch or concatenated prints which do not occur without calling base methods explicitly.

Common Pitfalls:
Confusing new (hiding) with override (polymorphic override via virtual).

Final Answer:
Derived2 class