C#.NET — Evaluate and predict the output: int num = 1, z = 5; if (!(num <= 0)) Console.WriteLine(++num + z++ + " " + ++z); else Console.WriteLine(--num + z-- + " " + --z);

Difficulty: Medium

Correct Answer: 7 7

Explanation:


Introduction / Context:
This problem tests your command of C#.NET expression evaluation, especially the interaction between prefix and postfix increment operators inside a conditional branch.



Given Data / Assumptions:

  • Initial values: num = 1, z = 5.
  • Condition checked: !(num <= 0).
  • Output concatenates two computed numeric expressions separated by a space.


Concept / Approach:
Remember that prefix increment (++x) increments first and then yields the incremented value, while postfix increment (x++) yields the current value and then increments. Also, the if condition is evaluated before either branch executes.



Step-by-Step Solution:

Step 1: Evaluate condition: num = 1 ⇒ (num <= 0) is false ⇒ !(false) is true. So enter the first branch.Step 2: Evaluate the first expression term ++num: num becomes 2, and the value contributed is 2.Step 3: Evaluate z++: contributes current z (5) to the sum, then z becomes 6 after this term.Step 4: Compute the sum for the left side of the space: 2 + 5 = 7.Step 5: Evaluate ++z for the right side: z is currently 6; ++z makes it 7 and yields 7.Step 6: Final printed output becomes "7 7".


Verification / Alternative check:
You can insert temporary writes to trace num and z after each operation, confirming z transitions 5 → 6 → 7 and num transitions 1 → 2.



Why Other Options Are Wrong:
A/B/C predict incorrect totals from mishandling prefix/postfix order; E is inapplicable because a definite result exists and compiles.



Common Pitfalls:
Mistaking the value contributed by z++ as 6 instead of 5, or assuming ++z on the right uses the previous z value without the earlier increment.



Final Answer:
7 7

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