C#.NET — Determine the printed output by evaluating bitwise precedence and Convert.ToBoolean. int i = 2, j = i; if (Convert.ToBoolean((i | (j & 5)) & (j - 25 * 1))) Console.WriteLine(1); else Console.WriteLine(0);

Introduction / Context:
This question checks precedence of bitwise operators, arithmetic evaluation, and the effect of Convert.ToBoolean on integer values in C#.

Given Data / Assumptions:

• i = 2, j = 2
• Expression: Convert.ToBoolean((i | j & 5) & (j - 25 * 1))
• Console prints 1 if the boolean is true, otherwise 0.

Concept / Approach:
Operator precedence: & (bitwise AND) binds tighter than | (bitwise OR). Arithmetic executes before bitwise. Convert.ToBoolean(x) is true for any nonzero integer and false for zero.

Step-by-Step Solution:

Verification / Alternative check:
You can reason by bit positions: value 2 has only the 2's bit set; -23 ends with ...1001 (for -23 it is 1111...1110 1001), making the 2's bit 0; their AND is 0.

Why Other Options Are Wrong:

• 1: would require a nonzero result after the final &.
• Compile Error / Run time Error: the code is valid and runs without exceptions.

Common Pitfalls:
Mixing up logical && with bitwise &, and assuming negative & positive is always nonzero. It depends on overlapping set bits.

Final Answer:
0