Right-triangle length: Determine the hypotenuse of a right triangle whose perpendicular sides measure 12 units and 18 units.

Difficulty: Easy

Correct Answer: 21.63

Explanation:


Introduction / Context:
The Pythagorean theorem is widely used across electrical engineering and physics, particularly in phasor magnitude calculations (e.g., combining orthogonal voltage or current components). Here, it is applied directly to a geometric right triangle to find the hypotenuse from two perpendicular legs.


Given Data / Assumptions:

  • Leg a = 12 units.
  • Leg b = 18 units.
  • Right triangle; hypotenuse c is opposite the right angle.


Concept / Approach:
Use the Pythagorean relation c^2 = a^2 + b^2. Then compute c = √(a^2 + b^2). This is the same vector magnitude formula used in phasor addition and impedance magnitude calculations in AC circuits.


Step-by-Step Solution:

Compute squares: a^2 = 12^2 = 144, b^2 = 18^2 = 324.Sum: a^2 + b^2 = 144 + 324 = 468.Take square root: c = √468.Simplify numerically: √468 ≈ 21.633 (since 21.633^2 ≈ 468).Rounded to two decimals: c ≈ 21.63.


Verification / Alternative check:
Express √468 = √(4 * 117) = 2√117. With √117 ≈ 10.8167, c ≈ 2 * 10.8167 ≈ 21.633, which matches the decimal computation and ensures consistent rounding.


Why Other Options Are Wrong:

  • 4.24, 3.46, 2.16: These are much smaller than either leg and cannot be a hypotenuse (which must be the longest side).


Common Pitfalls:

  • Accidentally subtracting the squares (appropriate only for projecting one component from hypotenuse and other leg).
  • Rounding too early and producing a noticeably inaccurate result.


Final Answer:
21.63

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