Magnetomotive force (mmf): For a 75-turn coil carrying 4 A, what is the mmf developed by the winding?

Difficulty: Easy

Correct Answer: 300 At

Explanation:


Introduction / Context:
Magnetomotive force (mmf) is the driving “cause” of magnetic flux in a magnetic circuit, analogous to electromotive force in electric circuits. Correctly computing mmf is essential when sizing coils and predicting magnetic field strength in cores and air gaps.


Given Data / Assumptions:

  • Number of turns N = 75.
  • Coil current I = 4 A.
  • We neglect leakage and assume steady DC current.


Concept / Approach:
The definition of mmf is F = N * I, with units ampere-turns (At). This simple relation underlies the calculation of field strength H = F / l (where l is magnetic path length) and subsequent flux density B = μ * H.


Step-by-Step Solution:

Write the mmf formula: F = N * I.Insert values: F = 75 * 4.Compute: F = 300 ampere-turns (At).


Verification / Alternative check:
If the mean magnetic path length were known, we could find H = F / l and then B = μ * H to corroborate physical magnitudes. The linear proportionality in F confirms that doubling turns or current doubles mmf.


Why Other Options Are Wrong:

  • 18.75 At or 30 At: These result from mistakenly multiplying or dividing by partial factors (e.g., using 0.25 A or 7.5 turns).
  • 187 At: A rounding or arithmetic slip; 75 * 4 is exactly 300.


Common Pitfalls:

  • Forgetting the “turns” factor; mmf is not just current.
  • Unit confusion: mmf is At, not volts or amperes alone.


Final Answer:
300 At

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