Effect of doubling source voltage: For a fixed resistor obeying Ohm’s law, if the applied voltage doubles, what happens to the circuit current and the resistance value?

Introduction / Context:
Ohm’s law describes linear resistive behavior, allowing predictions when voltage or current changes. Many troubleshooting tasks hinge on recognizing that fixed resistors do not change value merely because the applied voltage changes within ratings.

Given Data / Assumptions:

• Ideal, linear, temperature-stable resistor.
• Initial conditions follow Ohm’s law V = I * R.
• Voltage is doubled; no thermal or nonlinear effects considered.

Concept / Approach:

For a constant R, current I is proportional to voltage V. Thus, doubling V doubles I. The resistor’s value is a property of the component and remains unchanged (ignoring temperature coefficients and damage limits).

Step-by-Step Solution:

Verification / Alternative check:

Numerical example: R = 100 Ω, V = 10 V → I = 0.1 A. Double V to 20 V → I = 0.2 A (doubles), R stays 100 Ω.

Why Other Options Are Wrong:

• Resistance does not double or halve simply because voltage changes.
• Current does not remain the same if voltage changes across a fixed resistor.
• Current halving would occur if voltage halved, not doubled, for constant R.

Common Pitfalls:

• Overlooking resistor heating; extreme voltages can change resistance via temperature coefficients or cause failure, but that is outside ideal assumptions.

Final Answer:

Current doubles and resistance remains the same.