Demultiplexer behavior – does a demultiplexer take a single input signal and “turn it into a binary number,” or does it distribute that signal to one of many outputs based on select lines?

Difficulty: Easy

Correct Answer: Incorrect

Explanation:


Introduction / Context:
The names “encoder,” “decoder,” “multiplexer,” and “demultiplexer” can be confusing. This question clarifies the specific function of a demultiplexer (DEMUX) and whether it performs numeric code generation from an input signal.


Given Data / Assumptions:

  • DEMUX has one data input, multiple outputs, and select inputs.
  • An encoder generates a binary number from one-of-N active inputs.
  • A decoder translates a binary code into one-of-N outputs or display segments.


Concept / Approach:
A DEMUX routes a single input to one selected output among many, as determined by the select lines. It does not analyze the content of the input to produce a binary number; that function belongs to an encoder. Therefore, the claim that a DEMUX “turns an input into a binary number” is incorrect. Instead, a DEMUX is essentially the inverse of a multiplexer with respect to routing, not coding.


Step-by-Step Solution:

1) Identify DEMUX connections: one input D, outputs Y0..YN-1, selects S.2) Operation: Yi = D when S selects i; other outputs inactive.3) No code generation occurs; the signal is merely distributed.4) For generating a binary number from lines, use an encoder IC.


Verification / Alternative check:
Look at truth tables: 1-of-N DEMUX truth tables show output selection, while encoder truth tables map one-hot inputs to binary codes—two distinct behaviors.


Why Other Options Are Wrong:
“Correct” confuses DEMUX with encoder; references to “active-low” or specific device counts do not change the fundamental routing function.


Common Pitfalls:
Misapplying DEMUX in applications that require code generation or decoding; ensure you select the right primitive for the job.


Final Answer:
Incorrect

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