Team A's average height is 5 ft 11 in and Team B's is 6 ft 2 in. There are 20 players in A and 18 players in B. What is the overall average height (in inches)?

Introduction / Context:When combining groups with different averages and sizes, use weighted averages: convert all measures to a common unit, multiply each group’s average by its headcount, add, then divide by the total headcount.

Given Data / Assumptions:

• Team A: 20 players, average 5 ft 11 in = 71 inches.
• Team B: 18 players, average 6 ft 2 in = 74 inches.
• Find combined average in inches.

Concept / Approach:Overall average = (sum of all individual heights) / (total players). Equivalently, (average_A * count_A + average_B * count_B) / (count_A + count_B).

Step-by-Step Solution:

Verification / Alternative check:The result must lie between 71 and 74 and lean toward 71–74 weighted by 20 vs 18; 72.42 is consistent and closer to 71 because A has slightly more players.

Why Other Options Are Wrong:

• 72, 70, 70.22 inches: Do not match weighted computation.
• None of these: A precise correct value is available.

Common Pitfalls:Using an unweighted mean of 71 and 74 (which would be 72.5) or mixing feet and inches without converting.

Final Answer:72.42 inches