Difficulty: Medium
Correct Answer: 8.29 kN
Explanation:
Introduction / Context: Calculating the total hydrostatic thrust on vertical walls is fundamental for tank, dam, and gate design. For a rectangular vertical panel, the pressure varies linearly with depth, and the resultant equals the pressure at the centroid times the area.
Given Data / Assumptions:
Concept / Approach: For a vertical rectangle of height h and width b, the resultant hydrostatic force is F = ρ g A y_c, where A = b h and y_c = h/2 is the centroidal depth. This leverages the linear pressure distribution p = ρ g y.
Step-by-Step Solution:
Given h = 1.3 m, b = 1 m ⇒ A = 1.3 m^2. Centroid depth y_c = h/2 = 0.65 m. Compute F = ρ g A y_c = 1000 * 9.81 * 1.3 * 0.65 ≈ 8290 N = 8.29 kN.Verification / Alternative check: Average pressure on the panel = ρ g (h/2) = 9.81 * 0.65 ≈ 6.377 kPa; multiply by area 1.3 m^2 gives ≈ 8.29 kN, confirming the result.
Why Other Options Are Wrong: 2.89 kN is far too small; 9.28 kN is too large for 1.3 m depth; 28.9 kN corresponds to much larger depths or widths.
Common Pitfalls: Using p at the bottom times area (overestimates); forgetting that resultant acts at the centre of pressure, not at the centroid (important for moment calculations, though not needed for the magnitude here).
Final Answer: 8.29 kN per metre length of wall.
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