Induced current from induced voltage: A coil has an induced voltage of 200 mV. A 120 Ω resistor is connected across the coil. Determine the induced current.

Difficulty: Easy

Correct Answer: 1.7 mA

Explanation:


Introduction / Context:
Ohm’s law directly relates voltage, current, and resistance in a simple resistive load. When a coil produces an induced voltage and a resistor is connected across its terminals, the resulting current is set by I = V / R (ignoring coil resistance for this calculation, as typical in such questions).


Given Data / Assumptions:

  • Induced voltage, V = 200 mV = 0.2 V.
  • Load resistance, R = 120 Ω.
  • Assume purely resistive load and negligible source impedance for this basic computation.


Concept / Approach:

Apply Ohm’s law: I = V / R. Be careful with milli- prefixes to avoid unit mistakes. The answer will be in amperes; convert to milliamperes for a convenient final value.


Step-by-Step Solution:

Convert V: 200 mV = 0.2 V.Compute I: I = 0.2 / 120 = 0.001666… A.Express in mA: 0.001666… A ≈ 1.67 mA ≈ 1.7 mA.


Verification / Alternative check:

Reverse check: V = I * R ≈ 1.7 mA * 120 Ω = 0.204 V (rounding explains slight difference), consistent with the given voltage.


Why Other Options Are Wrong:

120 mA would require 14.4 V across 120 Ω. 16 mA and 12 mA correspond to 1.92 V and 1.44 V, respectively—far larger than 0.2 V. 0.17 mA is off by a factor of 10 due to unit slip.


Common Pitfalls:

Not converting millivolts to volts, or misreading 200 mV as 2 V or 0.02 V. Always convert before dividing.


Final Answer:

1.7 mA

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