Alphabet series – continue the pattern by constant jumps Sequence: R, U, X, A, D, ?
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AF
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BG
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CH
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DI
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EJ
Answer
Correct Answer: G
Explanation
Introduction / Context:This is a simple modular alphabet progression. The letters advance by a constant fixed jump, wrapping around after Z to continue from A. Recognizing the jump size reveals the next term immediately.
Given Data / Assumptions:
- Sequence: R, U, X, A, D, ?
- Alphabet positions A=1 through Z=26; wrap is applied when the sum exceeds 26.
Concept / Approach:Compute the shift from each letter to the next. If the shift is constant (e.g., +3), maintain it across the wrap point (Z→A) using modular arithmetic.
Step-by-Step Solution:
R(18) → U(21): +3U(21) → X(24): +3X(24) → A(1): +3 with wrap (24 + 3 = 27; 27 − 26 = 1)A(1) → D(4): +3Continue: D(4) → ? = 4 + 3 = 7 → G.Verification / Alternative check:Apply +3 from the beginning to confirm: R→U→X→A→D→G is perfectly consistent; every step is +3 under wrap.
Why Other Options Are Wrong:
- F (+2), H (+4), I (+5), J (+6) would each break the uniform +3 increment.
Common Pitfalls:Forgetting to wrap past Z when counting forward; miscounting positions and landing one letter off.
Final Answer:G