Number series — complete the sequence. Sequence: 4832, 5840, 6848, ?

Introduction / Context:
This problem focuses on recognizing a constant difference across terms (an arithmetic progression in large steps). Identifying the increment and applying it forward yields the missing number efficiently.

Given Data / Assumptions:

• Known terms: 4832, 5840, 6848.
• We test for constant addition between consecutive terms.
• No digit tricks are necessary if a clean common difference appears.

Concept / Approach:
Compute pairwise differences. If the differences are equal, the sequence is arithmetic with that common step. Then add the same step to the last given term to obtain the next value.

Step-by-Step Solution:
Difference 1: 5840 − 4832 = 1008. Difference 2: 6848 − 5840 = 1008. Common difference confirmed: 1008. Next term = 6848 + 1008 = 7856.

Verification / Alternative check:
Re-run subtraction to confirm: 7856 − 6848 = 1008, preserving the arithmetic pattern. No anomalies in carry or borrow operations occur.

Why Other Options Are Wrong:
7815/7846/7887: None equal 6848 + 1008; thus they break the constant step of 1008.

Common Pitfalls:
Overcomplicating with digit manipulations (reversals, inter-digit sums) when a simple constant difference fits perfectly.

Final Answer:
7856