Correct Answer: 260
Explanation:
From the given condition ,
cost incurred in path 2 is equal to that in path 3 then T3 = 0
Similarly ,equating cost of path 3 and path 4 T7 = 0
Equating cost of path 4 and path 5 we will get
260 + T6 + T8 = 230 + T5
⇒ T5 = T6 + T8 + 30
Equating cost of path 1 and path 2 we will get ,
240 +T1 = 260 + T2+ T4
or T1 = T2 + T4 + 20
For minimum total cost T1 = 20 and T5 = 30 then cost incurred is Rs 260.
Therefore , the minimum cost of travel from X to Y is Rs 260 .
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