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A walks 10 meters in front and 10 meters to the right. Then every time turning to his left, he walks 5, 15 and 15 meters respectively. How far is he now from his starting point?

5 meters
10 meters
20 meters
23 meters

Correct Answer: 5 meters

Explanation:

The movements of A are as shown in Figure (O to P, P to Q, Q to R, R to S and S to T)
Since TS = OP + QR, so T lies in line with O. A's distance from the starting point O = OT = (RS – PQ) = (15 – 10)m = 5 m.

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