From I, we find that the weight of one pole is (5 x 4) = 20 kg ,and so the weight of 10 poles is 200 kg.
Thus, I alone is sufficient.
From II. we have : (weight of 3 poles — weight of 2 poles) -= 20 kg or weight of one pole - 20 kg.
So. weight of 10 poles 200 kg.
Thus. II alone is also sufficient
