Correct Answer: Neither I nor II is sufficient
Explanation:
But, from II, M earns more than P i.e. D > N > M > P. Also, since P earns less than K and N earns less than only D, so we have: D>N>K>M>P or D>N>M> K > P.
Hence, either K or M earns more than only the least earner i.e. P.
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