Difficulty: Easy
Correct Answer: N_u = N / sqrt(H)
Explanation:
Introduction:
Unit quantities help compare turbines independent of head by normalizing performance to a head of 1 m. Unit speed indicates how fast the runner would turn at unit head, enabling fair comparison across different sites and tests.
Given Data / Assumptions:
Concept / Approach:
Under dynamically similar operation, characteristic velocities scale with sqrt(H). Therefore rotational speed, which is proportional to characteristic velocity divided by a length scale that is held fixed for a given machine, also scales with sqrt(H). To reduce from head H to unit head, divide by sqrt(H).
Step-by-Step Solution:
Velocity scale: V ∝ sqrt(g * H).Speed scale: N ∝ V / D with fixed D ⇒ N ∝ sqrt(H).Unit speed is the speed at H = 1 m: N_u = N / sqrt(H).
Verification / Alternative check:
The related unit relations are N_u = N / sqrt(H), Q_u = Q / sqrt(H), and P_u = P / H^(3/2). All consistently remove the head dependence for similar operation.
Why Other Options Are Wrong:
Common Pitfalls:
Mixing unit speed with specific speed, or using linear head scaling instead of the square-root law.
Final Answer:
N_u = N / sqrt(H)
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