2’s-complement arithmetic: Before adding or subtracting signed binary numbers, operands of different original widths must be sign-extended so that the operation occurs at the same bit width. Evaluate the claim that it is not necessary to have the same number of bits.

Difficulty: Easy

Correct Answer: Incorrect

Explanation:


Introduction / Context:
Signed arithmetic in digital systems is typically implemented with 2's complement representation. Correct results require consistent bit width so that sign bits align and carries/borrows propagate properly.


Given Data / Assumptions:

  • Operands may originate with different declared widths (e.g., 5-bit and 8-bit).
  • 2's complement addition/subtraction rules apply.
  • Overflow detection depends on consistent sign-bit alignment.


Concept / Approach:
When widths differ, you must sign-extend the smaller operand to the larger width, duplicating its sign bit into higher positions. Arithmetic is then performed at a single, common width. Saying “not necessary to have the same number of bits” is misleading; operations take place at one width after proper extension.


Step-by-Step Solution:

Identify operand widths n and m (assume n < m).Sign-extend the n-bit operand to m bits by repeating its MSB.Perform addition/subtraction at m bits.Evaluate overflow using sign-bit rules at width m.


Verification / Alternative check:
HDL synthesis and ISA specifications (e.g., sign-extension on load/extend instructions) formalize this requirement for correctness and overflow semantics.


Why Other Options Are Wrong:

  • Correct: Would imply mismatched widths can be directly added without extension.
  • Ambiguous / Cannot be determined: The rule is well-defined in 2's complement arithmetic.


Common Pitfalls:
Zero-extending negative numbers (wrong) or ignoring width differences, causing sign errors and incorrect overflow flags.


Final Answer:
Incorrect

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