Evaluating a specific NAND input case: For a two-input NAND gate with inputs A = 1 and B = 0 at the same time, determine whether the output equals 0 as claimed.

Introduction / Context:
Being able to quickly evaluate gate outputs for specific input combinations is a fundamental skill in digital logic. NAND is especially important because it is functionally complete (can build any logic) and used to construct latches and sequential elements when cross-coupled.

Given Data / Assumptions:

• Two-input NAND gate.
• Inputs: A = 1, B = 0 simultaneously.
• Ideal logic levels considered.

Concept / Approach:
The Boolean function for a NAND is Y = NOT(A · B). Compute the inner AND first: A · B = 1 · 0 = 0. Then invert: NOT(0) = 1. Therefore, for inputs (1,0) the output must be 1, not 0.

Step-by-Step Solution:

Verification / Alternative check:
Truth table row for NAND: for inputs 10 or 01, Y = 1. Only for 11 does Y = 0. This cross-validates the computation.

Why Other Options Are Wrong:
“Correct” contradicts the truth table. Environmental or drive-strength claims do not change the logical mapping and are irrelevant in the Boolean abstraction.

Common Pitfalls:
Confusing NAND with AND; forgetting that only the 11 case produces a LOW; misapplying precedence by trying to invert an incorrect intermediate result.

Final Answer:
Incorrect