Two signals g1(t) and g2(t) have average powers 4 and 5, respectively, and their zero-lag cross-correlation is 6. What is the average power of the sum signal g1(t) + g2(t)?

Difficulty: Medium

Correct Answer: 21

Explanation:

Introduction / Context:In signal analysis, the average power of a sum of signals depends on the individual powers and their correlation. This question checks understanding of how cross-correlation (at zero lag) contributes to the composite power of two simultaneous signals.

Given Data / Assumptions:

  • P1 = average power of g1(t) = 4.
  • P2 = average power of g2(t) = 5.
  • R12(0) = zero-lag cross-correlation between g1 and g2 = 6.
  • Signals are wide-sense stationary or time averages are meaningful for power calculation.

Concept / Approach:The time-average power of the sum is P{g1 + g2} = P1 + P2 + 2R12(0). The last term arises from the cross term 2g1(t)g2(t) when squaring and averaging. If R12(0) > 0, the sum’s power increases by twice the correlation value.

Step-by-Step Solution:

Start from (g1 + g2)^2 = g1^2 + g2^2 + 2g1 g2.Average both sides: P{g1 + g2} = P1 + P2 + 2 E[g1 g2].Given E[g1 g2] at zero lag = R12(0) = 6.So P{g1 + g2} = 4 + 5 + 2*6 = 21.

Verification / Alternative check:

If the signals were uncorrelated (R12(0) = 0), power would be 9. Positive correlation makes it larger, consistent with 21.

Why Other Options Are Wrong:

9: ignores correlation term.3 or 15: not consistent with formula P1 + P2 + 2R12(0).11: would correspond to R12(0) = 1, not 6.

Common Pitfalls:

Confusing correlation (expected product) with covariance; omitting the factor 2.

Final Answer:

21

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