A two-digit number has 3 as its units digit, and the sum of its digits equals one-seventh of the number itself. What is the number?

Difficulty: Easy

Correct Answer: 63

Explanation:


Introduction:
Represent the number using its tens digit and the fixed units digit 3. The given condition links the sum of digits to one-seventh of the number, producing a simple linear equation in the tens digit.



Given Data / Assumptions:

  • Number = 10t + 3.
  • Sum of digits = t + 3 = (1/7)(10t + 3).
  • Digits are 0–9 and t ≠ 0.


Concept / Approach:
Multiply both sides to clear the fraction; solve for t. Substitute back to obtain the number and verify.



Step-by-Step Solution:

t + 3 = (10t + 3)/7 → 7t + 21 = 10t + 3.18 = 3t → t = 6.Number = 10*6 + 3 = 63.


Verification / Alternative check:
Sum of digits 6 + 3 = 9; one-seventh of 63 = 9, condition satisfied.



Why Other Options Are Wrong:
43, 53, 73, 83 do not satisfy the one-seventh condition.



Common Pitfalls:
Forgetting to multiply both sides by 7 or miscomputing the sum of digits.



Final Answer:
63

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