Difficulty: Medium
Correct Answer: 32
Explanation:
Introduction / Context:This configuration uses tangent properties from a common external point. From any external point, the lengths of tangents drawn to a given circle are equal. Here A is a common external point to both circles, with one tangent line AX through X (touching both circles at X) and another common external tangent touching at Y and Z.
Given Data / Assumptions:
Concept / Approach:For a fixed circle and point A, all tangent lengths from A are equal. Hence, for the first circle, AY = AX = 16, and for the second circle, AZ = AX = 16. The segment YZ along the common external tangent is AY + AZ when measured between tangency points, giving YZ = 16 + 16 = 32 cm.
Step-by-Step Solution:
AY = AX = 16.AZ = AX = 16.YZ = AY + AZ = 32 cm.Verification / Alternative check:Power-of-a-point consistency at A confirms equal tangent lengths to each circle.
Why Other Options Are Wrong:18, 24, 16 undercount one or both tangent lengths.
Common Pitfalls:Thinking YZ equals |AY − AZ|; here both are equal to AX.
Final Answer:32
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