Difficulty: Medium
Correct Answer: Di,opt = 3.9 * Q^0.45 * ρ^0.13
Explanation:
Introduction / Context:
Early-stage pipe sizing often uses heuristics that relate a near-economic optimum diameter to flow rate and fluid properties. These correlations balance pumping power (friction losses) against installed cost (material and fabrication) and are useful for screening before detailed head-loss economics are performed.
Given Data / Assumptions:
Concept / Approach:
Optimum diameter scales positively with flow rate; higher density slightly favors a larger diameter due to higher mass flow at a given Q. Strong exponents on viscosity are uncommon in turbulent-flow heuristics because friction factor is only weakly dependent on μ in fully rough regimes. Thus, correlations with extreme viscosity exponents are not realistic for the intended screen.
Step-by-Step Solution:
Verification / Alternative check:
Back-of-the-envelope checks with common flows yield diameters in practical ranges (e.g., 2–12 inches) using the selected correlation, consistent with project heuristics.
Why Other Options Are Wrong:
Common Pitfalls:
Treating heuristics as code; final sizing should use detailed pressure-drop and lifecycle cost analysis for the selected service.
Final Answer:
Di,opt = 3.9 * Q^0.45 * ρ^0.13
Discussion & Comments