A train 110 m long moves at 60 km/h. In what time will it pass a man walking against (toward) the train at 6 km/h?

Introduction / Context:
When two objects move in opposite directions, their relative speed is the sum of their individual speeds. Passing a person requires covering only the train’s length at the relative speed.

Given Data / Assumptions:

• L_train = 110 m.
• Train speed = 60 km/h; Man speed = 6 km/h (toward the train).

Concept / Approach:
Relative speed v_rel = (60 + 6) km/h = 66 km/h. Convert v_rel to m/s; time t = L / v_rel_mps.

Step-by-Step Solution:

Verification / Alternative check:
If the man were stationary, time would be 110/(60*5/18) ≈ 6.6 s; walking toward the train reduces time to 6 s—consistent.

Why Other Options Are Wrong:
7⅓ s and 6⅔ s correspond to incorrect relative speeds; “Data inadequate” is incorrect because all needed values are given.

Common Pitfalls:
Subtracting speeds instead of adding for opposite directions; using platform distance instead of train length.

Final Answer:
6 seconds