Difficulty: Medium
Correct Answer: 360 kg
Explanation:
Introduction / Context:
This problem involves a mixture of two different profit percentages applied to different portions of the same commodity. It tests your ability to use weighted averages or alligation concepts on profit percentages. The total quantity and the overall profit percentage are given, and you must work backwards to find how much quantity was sold at the higher profit rate.
Given Data / Assumptions:
Concept / Approach:
We use a weighted average of profit percentages:
Step-by-Step Solution:
Step 1: Let x quintals be sold at 20% profit.
Step 2: Then 9 - x quintals are sold at 10% profit.
Step 3: Total profit (in percentage terms) on 9 quintals is given as 14%.
Step 4: Weighted average equation: (10 * (9 - x) + 20 * x) / 9 = 14.
Step 5: Simplify numerator: 10 * (9 - x) + 20 * x = 90 - 10x + 20x = 90 + 10x.
Step 6: So (90 + 10x) / 9 = 14.
Step 7: Multiply both sides by 9: 90 + 10x = 126.
Step 8: 10x = 126 - 90 = 36, so x = 36 / 10 = 3.6 quintals.
Step 9: Convert to kilograms: 3.6 quintals * 100 kg per quintal = 360 kg.
Verification / Alternative check:
Assume cost price per kg is Rs 1 to simplify:
Why Other Options Are Wrong:
540 kg: If this much were sold at 20% profit, the weighted average profit would be higher than 14%.
180 kg: This would make the average profit less than 14% because most wheat would earn only 10%.
720 kg: This would heavily favor the 20% side, leading to a much larger overall profit percentage.
Only 360 kg satisfies the overall 14% profit condition.
Common Pitfalls:
Students sometimes confuse the units, forgetting to convert quintals to kilograms or vice versa. Others incorrectly average the percentages as (10 + 20) / 2 = 15% without considering quantity distribution, which is wrong here because different quantities are sold at different rates. It is crucial to use the weighted average formula based on quantities, not just average the percentages blindly.
Final Answer:
The trader sells 360 kg of wheat at a 20% profit.
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