Difficulty: Medium
Correct Answer: 2 years
Explanation:
Introduction:
This question asks you to determine the time period for a compound interest investment when the principal, rate, and total compound interest are known. Being able to reverse engineer time is very important in aptitude tests involving financial mathematics.
Given Data / Assumptions:
Concept / Approach:
First, compute the final amount A using:
A = P + CIThen apply the compound interest formula:
A = P * (1 + r)^nRearrange to get:
(1 + r)^n = A / PWe then look for n such that the power of (1 + r) matches this ratio. Often n turns out to be a small integer in exam problems.
Step-by-Step Solution:
Step 1: Compute the final amount.A = P + CI = 30,000 + 4,347 = Rs 34,347Step 2: Use the compound interest formula.A = P * (1 + r)^n34,347 = 30,000 * (1 + 0.07)^n34,347 = 30,000 * (1.07)^nStep 3: Form the ratio.(1.07)^n = 34,347 / 30,000(1.07)^n ≈ 1.1449Step 4: Compare powers of 1.07.(1.07)^1 = 1.07 (too small)(1.07)^2 = 1.1449 (exact match)Thus, n = 2 years.
Verification / Alternative check:
Let us verify by forward calculation for 2 years:
A = 30,000 * (1.07)^2 = 30,000 * 1.1449 = Rs 34,347CI = A - P = 34,347 - 30,000 = Rs 4,347Since this matches the given compound interest, the period is confirmed as 2 years.
Why Other Options Are Wrong:
Common Pitfalls:
Some students try to assume simple interest and use linear relationships, which does not work for compound interest. Others do not compute the ratio correctly, or they round intermediate values too aggressively, leading to a wrong n. Always calculate A / P carefully and compare with standard powers of (1 + r).
Final Answer:
The money was invested for 2 years at 7% compound interest per annum.
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