Difficulty: Medium
Correct Answer: I θb = 12 ∠150° A, I θc = 12∠–90° A
Explanation:
Introduction / Context:This question checks phasor literacy for balanced three-phase systems. In a balanced generator (Δ or Y), the three phase quantities are equal in magnitude and separated by 120° in phase. Correctly assigning the angles for phases b and c after one phase is given is a core skill for system analysis, phasor diagrams, and power calculations.
Given Data / Assumptions:
Concept / Approach:For a positive sequence, the three phasors are separated by +120° steps when rotating from a to b to c (or equivalently, b lags a by 120°, c lags b by 120°). Because angles can be expressed modulo 360°, equivalent representations appear as additions or subtractions of 360° without changing the phasor.
Step-by-Step Solution:
Start with I_a = 12 ∠30° A.For 120° separation, one consistent set is: I_b = 12 ∠(30° + 120°) = 12 ∠150° A and I_c = 12 ∠(30° − 120°) = 12 ∠(−90°) A.These maintain equal magnitudes and 120° phasor spacing, satisfying a balanced positive sequence.Verification / Alternative check:Plot on a phasor diagram: one vector at 30°, the next at 150°, and the third at −90°. The separations are all 120° (from 30° to 150° is +120°, from 150° to −90° is +120°, from −90° to 30° is +120°), confirming balance and correct ordering.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:I θb = 12 ∠150° A, I θc = 12∠–90° A
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