A has double the money of B, and B has 50% more money than C. If the average money of A, B, and C is ₹ 12,000, how much money does A have?

Introduction:
This is a ratio–average blend. Express all amounts in terms of C, use the given average to determine C, and then compute A accordingly. Fractions are expected here because of the 50% relation (factor 1.5).

Given Data / Assumptions:

• A = 2B
• B = 1.5C
• Average(A, B, C) = ₹ 12,000

Concept / Approach:
Write all amounts in terms of C: A = 3C (since A = 2B and B = 1.5C → A = 3C), B = 1.5C, C = C. Then (A + B + C)/3 = 12,000 gives C. Finally compute A = 3C in fractional rupees to match the options.

Step-by-Step Solution:

Verification / Alternative check:
Compute B = 1.5C = 108000/11. Average of {216000/11, 108000/11, 72000/11} equals 12000, confirming consistency.

Why Other Options Are Wrong:
Other fractional values do not satisfy the average once A, B, C are checked under the given relations; ₹ 18,000 is not aligned with the ratio constraints.

Common Pitfalls:
Treating “50% more” as 1.5 times, not 1.5 plus C again (double-counting). Always translate words to exact multipliers first.

Final Answer:
₹ 216000/11