Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:
This question was incomplete originally (“The total resistance is 480 Ω.”). Applying the Recovery-First Policy, we minimally repair the stem to a standard parallel-resistor scenario. It now evaluates whether a common rule for identical resistors in parallel has been applied correctly. Such checks are routine in lab pre-calculations and troubleshooting.
Given Data / Assumptions:
Concept / Approach:
For n identical resistors in parallel, R_eq = R / n. With R = 1440 Ω and n = 3, the equivalent resistance should be 1440 / 3 = 480 Ω. This simple proportional rule arises because the total conductance is n/R, and the inverse gives the equivalent resistance decreasing with added branches.
Step-by-Step Solution:
Verification / Alternative check:
Compute using pairwise first: two 1.44 kΩ in parallel give 720 Ω. Then 720 Ω in parallel with another 1.44 kΩ yields (720 * 1440) / (720 + 1440) = (1,036,800) / 2160 = 480 Ω, confirming the result by a different route.
Why Other Options Are Wrong:
Common Pitfalls:
Mixing up series (R_eq = nR) with parallel (R_eq = R/n) for identical resistors; forgetting to convert kΩ to Ω before arithmetic; skipping a quick pairwise check that can catch arithmetic slips.
Final Answer:
Correct
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