Difficulty: Easy
Correct Answer: cutoff point
Explanation:
Introduction / Context:
The DC load line of a transistor amplifier is a straight line that shows all possible combinations of collector current and collector–emitter voltage for a fixed supply and load resistor. Understanding what the endpoints mean helps you quickly diagnose bias problems and choose a correct quiescent operating point, or Q-point, for linear amplification.
Given Data / Assumptions:
Concept / Approach:
The DC load line spans between two extremes: cutoff and saturation. At cutoff, the transistor conducts essentially no collector current, so the full supply appears across the collector–emitter terminals. At saturation, the transistor conducts heavily and the collector–emitter voltage falls near a small saturation value. The Q-point is chosen somewhere between these extremes to allow symmetrical signal swing.
Step-by-Step Solution:
Identify the upper endpoint: IC ≈ 0, VCE ≈ VCC.No collector current implies the transistor is not conducting in the collector path.By definition, that operating region is cutoff.Therefore, the upper point corresponds to the cutoff point.
Verification / Alternative check:
Plot the load line using VCE + IC * RC = VCC. When IC = 0, VCE = VCC, which is the high-voltage axis intercept, confirming it is the cutoff end. When VCE ≈ 0, IC ≈ VCC/RC, the lower point is saturation.
Why Other Options Are Wrong:
Minimum current gain: current gain depends on device and bias, not the geometric endpoint label.Quiescent point: that is a design choice inside the load line, not an endpoint by itself.Saturation point: located at the opposite (lower-voltage, higher-current) end.
Common Pitfalls:
Confusing the graphical position: upper on the VCE axis means high voltage and near zero current, which is cutoff, not saturation. Remember: cutoff → “off,” saturation → “on.”
Final Answer:
cutoff point
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