Three Consecutive Integers — Invariant Difference Given the sum of three consecutive integers (not necessarily provided explicitly), what is the constant difference between the first and the third integer in any such triple?

Introduction / Context:
The question focuses on a structural property of consecutive integers. Regardless of the actual values or their sum, three consecutive integers always have fixed spacing. Recognizing this invariant lets you answer without computing any specific numbers, which is an important reasoning shortcut in aptitude tests.

Given Data / Assumptions:

• The integers are consecutive; call them n − 1, n, n + 1.
• “Consecutive” means the step size is 1 between neighbors.
• We are asked for the difference between the first and the third.

Concept / Approach:
If the three numbers are (n − 1), n, and (n + 1), then the first is n − 1 and the third is n + 1. Their difference equals (n + 1) − (n − 1) = 2. This result does not depend on the specific n or the actual sum; it is purely structural and therefore universal to any such triple.

Step-by-Step Solution:
Represent the triple: first = n − 1, middle = n, third = n + 1.Compute difference: (n + 1) − (n − 1) = 2.Conclude: The difference is always 2.No additional numeric data are required.

Verification / Alternative check:
Try sample triples: (5, 6, 7) → 7 − 5 = 2; (−3, −2, −1) → (−1) − (−3) = 2. The result is consistent across all cases.

Why Other Options Are Wrong:
“One” or “Three” contradict the exact spacing; “Either (A) or (B)” is logically impossible for a fixed invariant; “Zero” would require the first and third to be equal, which never occurs for consecutive integers.

Common Pitfalls:
Confusing “consecutive integers” with “consecutive odd/even integers,” where spacing differs; overcomplicating by trying to use the sum when it is unnecessary.

Final Answer:
Two