Difficulty: Easy
Correct Answer: 15:1
Explanation:
Introduction / Context:The air–fuel ratio (AFR) at which exactly enough oxygen is supplied to burn all the fuel without excess air or fuel is called stoichiometric. For petrol engines, this AFR is a key target for three-way catalysts and closed-loop lambda control to minimize emissions while maintaining good drivability.
Given Data / Assumptions:
Concept / Approach:
For iso-octane as a surrogate, the balanced oxidation is C8H18 + 12.5 O2 → 8 CO2 + 9 H2O. Air contains about 21% O2 by volume (≈23% by mass), so the mass of air needed is roughly 14.7 times the mass of fuel. Rounded to a practical figure used in calibration and textbooks, the stoichiometric AFR for petrol is about 15:1 by mass.
Step-by-Step Solution:
Start with idealized fuel: C8H18.Compute O2 moles: 12.5 per mole of fuel for complete oxidation.Convert O2 to air mass using O2 mass fraction in air.Obtain AFR ≈ 14.7:1 → commonly rounded to 15:1.Verification / Alternative check:
Engine calibrations use lambda = 1 at AFR ≈ 14.7:1. Emissions control and stoichiometric operation reinforce this canonical value.
Why Other Options Are Wrong:
10:1 is rich (used for power enrichment). 20:1 and 25:1 are lean burn values associated with fuel economy but higher NOx without special strategies. 12.5:1 is a common rich power AFR for knock avoidance and cooling but not stoichiometric.
Common Pitfalls:
Mixing up volume-based and mass-based ratios; assuming one exact value for all petrol blends—the 14.7–15:1 figure is an accepted practical average.
Final Answer:
15:1
Discussion & Comments