Air–Fuel Ratio for Petrol – Stoichiometric (Chemically Correct) Mixture Select the approximate stoichiometric air–fuel ratio by mass for a conventional petrol (gasoline) engine mixture used for complete combustion.

Difficulty: Easy

Correct Answer: 15:1

Explanation:


Introduction / Context:
The air–fuel ratio (AFR) at which exactly enough oxygen is supplied to burn all the fuel without excess air or fuel is called stoichiometric. For petrol engines, this AFR is a key target for three-way catalysts and closed-loop lambda control to minimize emissions while maintaining good drivability.


Given Data / Assumptions:

  • Petrol approximated as a representative hydrocarbon (e.g., iso-octane C8H18).
  • Complete combustion to CO2 and H2O assumed.
  • Mass-based AFR values are considered.


Concept / Approach:

For iso-octane as a surrogate, the balanced oxidation is C8H18 + 12.5 O2 → 8 CO2 + 9 H2O. Air contains about 21% O2 by volume (≈23% by mass), so the mass of air needed is roughly 14.7 times the mass of fuel. Rounded to a practical figure used in calibration and textbooks, the stoichiometric AFR for petrol is about 15:1 by mass.


Step-by-Step Solution:

Start with idealized fuel: C8H18.Compute O2 moles: 12.5 per mole of fuel for complete oxidation.Convert O2 to air mass using O2 mass fraction in air.Obtain AFR ≈ 14.7:1 → commonly rounded to 15:1.


Verification / Alternative check:

Engine calibrations use lambda = 1 at AFR ≈ 14.7:1. Emissions control and stoichiometric operation reinforce this canonical value.


Why Other Options Are Wrong:

10:1 is rich (used for power enrichment). 20:1 and 25:1 are lean burn values associated with fuel economy but higher NOx without special strategies. 12.5:1 is a common rich power AFR for knock avoidance and cooling but not stoichiometric.


Common Pitfalls:

Mixing up volume-based and mass-based ratios; assuming one exact value for all petrol blends—the 14.7–15:1 figure is an accepted practical average.


Final Answer:

15:1

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