Difficulty: Hard
Correct Answer: 65°
Explanation:
Introduction / Context:
This problem combines two classic geometry ideas: (1) isosceles triangles formed by equal chords or equal segments in a circle, and (2) the tangent-chord theorem (also called the alternate segment theorem). The goal is to find the angle between a tangent at T and the chord TS, which equals the angle in the opposite segment subtended by chord TS.
Given Data / Assumptions:
Concept / Approach:
First use isosceles triangle properties: if TR = TS, then base angles at R and S are equal. Next apply the tangent-chord theorem: the angle between the tangent at T and chord TS equals the angle in the alternate segment, which is the angle subtended by chord TS at the opposite point on the circle (here point R). So ∠PTS equals ∠TRS.
Step-by-Step Solution:
Given TR = TS, triangle RST is isosceles with base RS
So base angles are equal: ∠TRS = ∠RST
Given ∠RST = 65°, therefore ∠TRS = 65°
Now use tangent-chord (alternate segment) theorem:
Angle between tangent at T and chord TS equals the angle in the opposite segment subtended by TS
That opposite-segment angle is ∠TRS
So ∠PTS = ∠TRS = 65°
Verification / Alternative check:
We can also find ∠RTS = 180° - 65° - 65° = 50°, consistent with an isosceles triangle. The tangent-chord theorem does not depend on this 50°, but it supports internal consistency of the given triangle angles.
Why Other Options Are Wrong:
130° is the exterior angle at S if incorrectly doubled, but ∠PTS is not defined that way.
115° and 55° come from mixing up which angle corresponds to the alternate segment.
45° is an unrelated guess and does not match any derived circle angle relationship here.
Common Pitfalls:
Confusing the tangent-chord theorem with the angle at the center theorem, or using the wrong point for the “alternate segment” angle. Another frequent mistake is forgetting that TR = TS implies angles at R and S are equal, not angles at T and S.
Final Answer:
∠PTS = 65°
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