Difficulty: Easy
Correct Answer: √(sec^2 A - 1)
Explanation:
Introduction / Context:
This question is designed to test your understanding of fundamental trigonometric identities, especially the Pythagorean identity involving tan A and sec A. When tan A is expressed in terms of sec A, you must recall that sec^2 A and tan^2 A are related in a simple way, which lets you write tan A as a square root expression involving sec^2 A.
Given Data / Assumptions:
Concept / Approach:
The key identity is sec^2 A = 1 + tan^2 A. From this, we can isolate tan^2 A in terms of sec^2 A and then take the square root to express tan A as a function of sec A. The square root introduces a plus or minus sign, but in the context of many aptitude questions with standard ranges for A, we usually choose the principal value consistent with the problem setting.
Step-by-Step Solution:
Verification / Alternative check:
Take a specific angle such as A = 45 degrees. Then tan 45° = 1, so x = 1. Also, sec 45° = √2, so sec^2 45° = 2. Now compute √(sec^2 45° - 1) = √(2 - 1) = √1 = 1, which matches tan 45°. This confirms that the identity and the chosen option are correct.
Why Other Options Are Wrong:
Common Pitfalls:
Students sometimes confuse the identities sec^2 A = 1 + tan^2 A and cosec^2 A = 1 + cot^2 A, or mix up which identity uses plus or minus. Another common mistake is to assume tan^2 A = 1 - sec^2 A, which is incorrect and reverses the signs. Remembering the correct Pythagorean forms is essential here.
Final Answer:
√(sec^2 A - 1)
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