Difficulty: Easy
Correct Answer: None of these
Explanation:
Introduction / Context:
This question illustrates a classic pitfall: when two classes are both contained in a larger class, we cannot infer that those two classes overlap each other. “All schools are books” and “some pens are books” do not guarantee any common element between schools and pens.
Given Data / Assumptions:
Concept / Approach:
Use subset propagation carefully. From “some colleges are schools” and “all schools are books,” we can confidently move those specific colleges into the books set. However, moving from pens to schools (or colleges to pens) cannot be done without an explicit connecting statement beyond the shared superset “books.”
Step-by-Step Solution:
III: “Some colleges are books.” Since some colleges are schools and every school is a book, those colleges are books. III follows.I: “Some colleges are pens.” No link connects colleges to pens except both relate to books. Shared supersets do not imply overlap. I does not follow.II: “Some pens are schools.” Again, pens and schools both sit within books, but that does not force any intersection. II does not follow.
Verification / Alternative check:
Create a model where the “pens inside books” subset is entirely separate from the “schools (and thus colleges) inside books” subset. All premises hold; only III is true. Because no option lists “Only III,” the correct choice is “None of these.”
Why Other Options Are Wrong:
Common Pitfalls:
Assuming that two classes contained in the same larger class must overlap; ignoring that “some” statements identify only part of a set.
Final Answer:
None of these
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