Difficulty: Easy
Correct Answer: 253
Explanation:
Introduction / Context:Square-root questions on perfect squares can be solved quickly by testing nearby squares and using last-digit and tens-place cues. Here we locate √64009 by bracketing between known squares around 250^2.
Given Data / Assumptions:
Concept / Approach:For k near 250, compute (250 + d)^2 = 250^2 + 2*250*d + d^2 to step upward efficiently. Also, the last digit 9 suggests roots ending in 3 or 7 for odd squares ending with 9; among options, 253 is a candidate.
Step-by-Step Solution:251^2 = 63001252^2 = 63504253^2 = 64009 (exact match)
Verification / Alternative check:Use (250 + 3)^2 = 250^2 + 1500 + 9 = 62500 + 1500 + 9 = 64009, confirming the result.
Why Other Options Are Wrong:352, 523, and 532 produce squares far from 64009; 245^2 = 60025, which is too small.
Common Pitfalls:Guessing without bracketing; ignoring simple expansion (a + b)^2 = a^2 + 2ab + b^2 which speeds mental checks.
Final Answer:253
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