What is the specific weight (unit weight) of water in SI units, to the nearest standard value?

Difficulty: Easy

Correct Answer: 9.81 kN/m^3

Explanation:


Introduction:
Specific weight (unit weight) is weight per unit volume. For water at standard conditions, engineers commonly use a convenient rounded value for design and quick checks.


Given Data / Assumptions:

  • Standard reference conditions near 4°C to 20°C.
  • Acceleration due to gravity g ≈ 9.81 m/s^2.


Concept / Approach:
Specific weight gamma = rho * g. For water, rho ≈ 1000 kg/m^3. Therefore gamma ≈ 1000 * 9.81 N/m^3 = 9810 N/m^3 = 9.81 kN/m^3. This is the widely accepted design value in SI.


Step-by-Step Solution:
1) Take rho_w ≈ 1000 kg/m^3.2) Multiply by g: 1000 * 9.81 = 9810 N/m^3.3) Convert to kN: 9810 N/m^3 = 9.81 kN/m^3.


Verification / Alternative check:
Using more precise densities changes only the third decimal place of gamma, not the standard rounded 9.81 kN/m^3 used for hand calculations.


Why Other Options Are Wrong:

  • 981 kN/m^3: Off by a factor of 100; implies rho ≈ 100,000 kg/m^3.
  • 9.81 N/m^3: Off by a factor of 1000; would imply extremely low density.
  • 9810 kN/m^3: Off by a factor of 1000; numerically equals 9.81 MN/m^3, not water.


Common Pitfalls:

  • Mixing N/m^3 and kN/m^3 units.
  • Using mass density (kg/m^3) directly as specific weight without multiplying by g.


Final Answer:
9.81 kN/m^3

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