Centrifugal Pump — Specific Speed (Ns) Which formula correctly gives the specific speed of a centrifugal pump in terms of rotational speed N (rpm), discharge Q, and head H (m)?
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ANs = N * sqrt(Q) / H^(3/4)
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BNs = N * Q / H
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CNs = N * sqrt(P) / H^(5/4)
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DNs = N / H^(3/2)
Answer
Correct Answer: Ns = N * sqrt(Q) / H^(3/4)
Explanation
Introduction:Specific speed groups pumps of different sizes by hydraulic similarity. It indicates the impeller style best suited to a duty point, varying from radial (low Ns) to axial (high Ns) designs.
Given Data / Assumptions:
- N in rpm, Q in m^3/s (or consistent units), H in m.
- Geometric similarity and similar efficiency near the best efficiency point.
Concept / Approach:For pumps, specific speed is based on discharge, not power. From affinity/similarity, the widely used empirical form is Ns = N * Q^0.5 / H^0.75 (up to a constant depending on units). This correlates duty with impeller type: low Ns for radial, medium for mixed flow, high for axial-flow pumps.
Step-by-Step Solution:Start with model law: Q ∝ N * D^3 and H ∝ N^2 * D^2.Eliminate D to obtain dimensionless grouping linking N, Q, H.Arrive at Ns ∝ N * Q^0.5 / H^0.75 (rpm-based form).
Verification / Alternative check:Catalog charts mapping Ns to impeller geometry confirm the correlation trends.
Why Other Options Are Wrong:N * Q / H: wrong exponents; not similarity-consistent.N * sqrt(P) / H^(5/4): that is a turbine-specific-speed form using power.N / H^(3/2): omits discharge term entirely.
Common Pitfalls:Confusing pump Ns (uses Q) with turbine Ns (uses P).
Final Answer:Ns = N * sqrt(Q) / H^(3/4)