Difficulty: Easy
Correct Answer: Ns = N * sqrt(Q) / H^(3/4)
Explanation:
Introduction:
Specific speed groups pumps of different sizes by hydraulic similarity. It indicates the impeller style best suited to a duty point, varying from radial (low Ns) to axial (high Ns) designs.
Given Data / Assumptions:
Concept / Approach:
For pumps, specific speed is based on discharge, not power. From affinity/similarity, the widely used empirical form is Ns = N * Q^0.5 / H^0.75 (up to a constant depending on units). This correlates duty with impeller type: low Ns for radial, medium for mixed flow, high for axial-flow pumps.
Step-by-Step Solution:
Start with model law: Q ∝ N * D^3 and H ∝ N^2 * D^2.Eliminate D to obtain dimensionless grouping linking N, Q, H.Arrive at Ns ∝ N * Q^0.5 / H^0.75 (rpm-based form).
Verification / Alternative check:
Catalog charts mapping Ns to impeller geometry confirm the correlation trends.
Why Other Options Are Wrong:
N * Q / H: wrong exponents; not similarity-consistent.N * sqrt(P) / H^(5/4): that is a turbine-specific-speed form using power.N / H^(3/2): omits discharge term entirely.
Common Pitfalls:
Confusing pump Ns (uses Q) with turbine Ns (uses P).
Final Answer:
Ns = N * sqrt(Q) / H^(3/4)
Discussion & Comments