Longest pole across a rectangular room (space diagonal): A room measures 12 m (length) × 9 m (width) × 8 m (height). Find the length of the longest pole that can fit inside.

Difficulty: Easy

Correct Answer: 17 m

Explanation:


Introduction / Context:
The longest stick that fits in a rectangular room aligns with the space diagonal of the cuboid. This classic 3D Pythagoras application appears often in aptitude tests.



Given Data / Assumptions:

  • L = 12 m, W = 9 m, H = 8 m
  • Space diagonal d = √(L^2 + W^2 + H^2)


Concept / Approach:
Apply the 3D extension of Pythagoras: d = √(a^2 + b^2 + c^2) for a cuboid with edges a, b, c.



Step-by-Step Solution:
d = √(12^2 + 9^2 + 8^2) = √(144 + 81 + 64)d = √289 = 17 m



Verification / Alternative check:
Compute floor diagonal first: √(12^2 + 9^2) = √225 = 15; then √(15^2 + 8^2) = √(225 + 64) = √289 = 17. Same result.



Why Other Options Are Wrong:
12 m and 14 m are below the space diagonal; 21 m exceeds any dimension; 15 m is only the floor diagonal, not the space diagonal.



Common Pitfalls:
Using only the floor diagonal; mixing up dimensions; arithmetic errors when squaring and adding.



Final Answer:
17 m

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