Ohm’s law application: A 24 V source supplies a 100 Ω load. Calculate the load current and express the answer with appropriate SI units.

Introduction / Context:
Ohm’s law is the backbone of basic circuit analysis. Converting between volts, ohms, and amperes is routine when checking supply sizing, fuse ratings, and expected temperature rise. This problem reinforces current calculation and correct use of SI prefixes for clear communication.

Given Data / Assumptions:

• Supply voltage V = 24 V (dc or rms equivalently for a purely resistive load).
• Load resistance R = 100 Ω.
• Assume ideal source and purely resistive load with steady-state conditions.

Concept / Approach:
Ohm’s law states I = V / R. For resistive loads, this directly yields the current. After calculation, express the result using a convenient prefix; milliampere is common for sub-ampere currents (1 A = 1000 mA).

Step-by-Step Solution:

Verification / Alternative check:
Cross-check power: P = V * I = 24 * 0.24 = 5.76 W. Alternatively, P = V^2 / R = 576 / 100 = 5.76 W. Agreement confirms the current is correct.

Why Other Options Are Wrong:

• 2.4 A: Ten times too large; would require R = 10 Ω at 24 V.
• 24 mA or 2.4 mA: Underestimates current by factors of 10 and 100 respectively.

Common Pitfalls:
Dropping a zero when dividing by 100 or misapplying prefixes (confusing mA with A). Always include units at every step.

Final Answer:
240 mA