Balance an equation with products of mixed numbers Compute the missing term ? such that 15 2/3 × 3 1/6 + 6 1/3 = 11 7/18 + ?.

Introduction / Context:
This question requires accurate conversion of mixed numbers to improper fractions, multiplication of fractions, and isolating a missing term in an equality. Precision with numerators and denominators is crucial when dealing with non-integer products.

Given Data / Assumptions:

• Equation: 15 2/3 × 3 1/6 + 6 1/3 = 11 7/18 + ?
• 15 2/3 = 47/3, 3 1/6 = 19/6, 6 1/3 = 19/3, 11 7/18 = 205/18.

Concept / Approach:
Convert all mixed numbers to improper fractions. Multiply fractions by multiplying numerators and denominators. Then add the known terms on the left, and subtract the right-hand known term to solve for the unknown ?. Reduce the final fraction if possible.

Step-by-Step Solution:
Left product: (47/3) × (19/6) = 893/18.Add 6 1/3 = 19/3 = 114/18.Left sum: 893/18 + 114/18 = 1007/18.Right known term: 11 7/18 = 205/18.Solve for ?: 1007/18 = 205/18 + ? → ? = (1007 − 205)/18 = 802/18 = 401/9.

Verification / Alternative check:
Convert 401/9 back to a mixed number: 44 5/9. Substituting creates equality on both sides, confirming correctness.

Why Other Options Are Wrong:
395/9, 1374/9, and 297/9 do not balance the equation; therefore, “None of these” is the correct choice since 401/9 is not listed among the given options.

Common Pitfalls:
Misconverting mixed numbers; forgetting to bring terms to a common denominator; arithmetic slips when subtracting numerators.

Final Answer:
None of these