Difficulty: Easy
Correct Answer: using high-speed clock signals
Explanation:
Introduction / Context:
Serial communication speed is typically expressed as baud or bits per second. Improving throughput involves increasing symbol rate and/or bits per symbol, within the limits of channel bandwidth, noise, and protocol constraints. This question targets the most direct lever in basic digital links.
Given Data / Assumptions:
Concept / Approach:
For clocked serial links, the symbol rate is set by clock frequency. Raising the clock increases the number of symbols per second, thereby increasing throughput, provided the channel can support the higher bandwidth without excessive intersymbol interference or jitter.
Step-by-Step Solution:
Recognize throughput B ≈ symbols_per_second * bits_per_symbol.With the same coding, bits_per_symbol is constant.Increase symbols_per_second by raising the clock frequency → higher bit rate.
Verification / Alternative check:
Interfaces like SPI/UART clearly specify maximum clock/baud rates; increasing from 1 MHz to 5 MHz SPI, for example, yields a 5× raw throughput increase if timing margins are met.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
using high-speed clock signals
Discussion & Comments