Difficulty: Easy
Correct Answer: Closed-loop transfer function
Explanation:
Introduction / Context:
The Routh–Hurwitz stability test determines whether all roots of a polynomial lie in the left half of the s-plane. In control systems, we apply it to the characteristic equation of the closed-loop system to assess stability without computing roots explicitly.
Given Data / Assumptions:
Concept / Approach:
Stability of the actual, operating loop depends on the poles of the closed-loop transfer function. The Routh array is built from the coefficients of that closed-loop characteristic polynomial. While open-loop transfer functions are used to derive the closed-loop characteristic equation (e.g., 1 + L(s) = 0), the Routh test itself is applied to the resulting closed-loop denominator.
Step-by-Step Solution:
Form L(s) from plant and controller.Write characteristic equation 1 + L(s) = 0 and expand to get the polynomial.Construct the Routh array with those coefficients to test sign changes in the first column.
Verification / Alternative check:
Textbooks consistently define the “characteristic equation” as the closed-loop denominator; examples of gain margin design via Routh all start from the closed-loop polynomial.
Why Other Options Are Wrong:
Open-loop alone does not reflect feedback stability.“Either/Neither” misstates the criterion’s basis.Controller-only polynomials ignore plant dynamics.
Common Pitfalls:
Applying Routh to the numerator or to open-loop polynomials; forgetting to include dead time approximations (if any) in the characteristic polynomial used.
Final Answer:
Closed-loop transfer function
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