Difficulty: Medium
Correct Answer: 2.4
Explanation:
Introduction / Context:
This problem tests how to convert a trigonometric ratio (cosec) into side ratios in a right-angled triangle and then scale those ratios using a given side length. It combines knowledge of cosec X, the definition of sine, and the idea of similar right-triangle side triples.
Given Data / Assumptions:
Concept / Approach:
Use cosec X = hypotenuse/opposite. From cosec X = 13/12, we get XZ:YZ = 13:12. A right triangle with sides in the ratio 5:12:13 is a standard Pythagorean triple, meaning the adjacent side to angle X is 5 parts when hypotenuse is 13 parts and opposite is 12 parts.
Step-by-Step Solution:
cosec X = 13/12 means XZ / YZ = 13/12
So let XZ = 13k and YZ = 12k for some scale factor k
Because angle Y is 90 degrees, Pythagoras applies: XY^2 + YZ^2 = XZ^2
XY^2 = XZ^2 - YZ^2 = (13k)^2 - (12k)^2 = 169k^2 - 144k^2 = 25k^2
So XY = 5k
Given XY = 1 cm, we get 5k = 1 => k = 0.2
Then YZ = 12k = 12 * 0.2 = 2.4 cm
Verification / Alternative check:
Compute hypotenuse: XZ = 13k = 2.6 cm. Check: 1^2 + 2.4^2 = 1 + 5.76 = 6.76 and 2.6^2 = 6.76, so the triangle is consistent.
Why Other Options Are Wrong:
2.0 and 1.8 are too small; they would not keep the 12:13 sin ratio with XY = 1.
2.6 confuses YZ with the hypotenuse XZ.
1.5 corresponds to a different side ratio and fails the Pythagoras check with hypotenuse 2.6.
Common Pitfalls:
Mixing up which side is opposite angle X (it is YZ), or treating XY as the opposite side. Another common mistake is assuming cosec is opposite/hypotenuse instead of hypotenuse/opposite.
Final Answer:
YZ = 2.4 cm
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