All letters of the given series are written in reverse order. In that reversed series, what letter is 8th to the right of the 7th from the left? Original series: C E B A C D B C D A C E B E D C A B A D A C E D U B A U B D B U

Introduction / Context:
Indexing problems in reversed sequences are common in verbal reasoning. A direct reversal and recount is possible but time-consuming. A position-mapping shortcut avoids rewriting the sequence and reduces errors.

Given Data / Assumptions:

• Original sequence has 32 letters: C E B A C D B C D A C E B E D C A B A D A C E D U B A U B D B U.
• Task in reversed series: find the letter 8th to the right of the 7th from the left.
• Counting is 1-based (7th means index 7, 8th to the right means +8 positions).

Concept / Approach:
In the reversed sequence, the element 8 to the right of the 7th from the left is the element at position 7 + 8 = 15 from the left (in the reversed array). The 15th-from-left in the reversed sequence equals the 15th-from-right in the original sequence. If the original has N elements, the k-th from right is at position N - k + 1 from the left.

Step-by-Step Solution:

Verification / Alternative check:
You can explicitly reverse the sequence and count to the 15th position; it will also be B, confirming the mapping shortcut.

Why Other Options Are Wrong:

• A, C, D: Each corresponds to different positions; none matches the 18th-from-left in the original (or 15th-from-left in the reversed).

Common Pitfalls:
Forgetting that moving 8 to the right after selecting the 7th adds to 15 total, or misapplying the N - k + 1 mapping. Another common mistake is switching to 0-based counting mid-way.

Final Answer:
B