Difficulty: Easy
Correct Answer: 6 kHz
Explanation:
Introduction / Context:
Bandwidth measures the span between the two half-power (−3 dB) frequencies of a resonant network. It captures how wide the useful passband is for filters and tuned circuits, independent of the absolute center frequency.
Given Data / Assumptions:
Concept / Approach:
By definition, bandwidth is the simple arithmetic difference between the upper and lower cutoff frequencies. No further computation is needed unless a quality factor or center frequency is required.
Step-by-Step Solution:
Verification / Alternative check:
Center frequency f0 could be estimated as √(f1 * f2) ≈ √(7 * 13) kHz ≈ 9.54 kHz, and Q = f0 / BW ≈ 9.54 / 6 ≈ 1.59 (reasonable), reinforcing that the bandwidth arithmetic is correct.
Why Other Options Are Wrong:
13 kHz and 7 kHz are the individual cutoff frequencies, not the span between them. 20 kHz adds instead of subtracting, which is not the definition of bandwidth.
Common Pitfalls:
Confusing center frequency, arithmetic mean, or geometric mean with bandwidth; subtracting in the wrong order.
Final Answer:
6 kHz
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