According to question ,
Here ,we will eliminate the options one by one. Option (A) cannot be true as there are many routes that satisfy the given condition. Option (C) is also not true as we can have a route starting from D (e.g. DEBDCBAC).
The route need not necessarily end at E, which is apparent. Option B satisfies all the conditions.
Hence , A route can either start at C or end at C, but not both.

On the basis of above given figure , we can see that
City A is connected by 2 roads, B by 4 roads, C by 3 roads, D by 3 roads and E by 2 roads.
For a city to be starting city for such a route, it has to be connected by odd number of roads.
Hence the required answer is 2, i.e. C and D.

As per the above result ,
Route -1 :- 5 + AB = 13 ? AB = 13 - 5 = 8 km
Hence , required distance between A and B is 8 km .

From the above result length of route -2 = 11 km
Therefore , the length of route -2 is 11 km .

As per the given above figure , we can see that
The number of routes from P to Q = 2 + 4 = 6
Hence , the number of routes from P to Q is 6 .